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JAMB MathematicsStudy notes & practice

Build confidence with calculations, algebra, geometry, calculus and statistics.

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Foundation revision notes and original practice. These lessons explain major methods through selected worked examples. Wider multi-step and mixed-topic practice is still needed.

What these revision notes cover
  • These lessons explain major methods through selected worked examples. Wider multi-step and mixed-topic practice is still needed.
  • Use the full syllabus to check what remains to revise; lesson counts do not measure mastery.

01 Number and numeration

Number bases and modular arithmetic

Read this lesson

What you should be able to do

  • Convert whole numbers and fractions between bases
  • Work with remainders in modular arithmetic

Understand it

Place value depends on the base. In base b, places to the left of the point represent powers b⁰, b¹, b² and so on; places to the right represent b⁻¹, b⁻² and so on. Each digit must be smaller than the base.

To convert from base ten, divide the whole-number part repeatedly by the new base and read the remainders upwards. Convert a fractional part by repeated multiplication, reading the whole-number parts in order.

Working modulo n means comparing remainders after division by n. For example, 17 and 5 are congruent modulo 12. Perform ordinary addition or multiplication and then reduce the result to its remainder.

Work through an example

Convert 101.1₂ to base ten.

Explanation: 1×2² + 0×2¹ + 1×2⁰ + 1×2⁻¹ = 4 + 0 + 1 + 0.5 = 5.5.

Watch out: A base-two number cannot contain the digit 2.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

What is 1101₂ in base ten?

  1. 12
  2. 11
  3. 13
  4. 14
Show answer and explanation

Answer C: 13

Read the binary place values from right to left as 1, 2, 4 and 8. Then 1101₂ = (1 × 8) + (1 × 4) + (0 × 2) + (1 × 1) = 13. The zero contributes nothing, but its place value must still be kept.

Question 2

What is 23 + 9 modulo 7?

  1. 2
  2. 1
  3. 3
  4. 4
Show answer and explanation

Answer D: 4

First add: 23 + 9 = 32. Divide by 7: 32 = (4 × 7) + 4, so the least non-negative remainder is 4. The quotient happens to be 4 as well in this example; modulo asks for the remainder, not the quotient.

02 Number and numeration

Fractions, percentages and financial arithmetic

Read this lesson

What you should be able to do

  • Calculate fractions, ratios and percentage changes
  • Apply stated interest, share and tax rates

Understand it

Use a common denominator to add or subtract fractions. Multiplication works directly across numerators and denominators; division by a fraction means multiplication by its reciprocal. A ratio divides a total into a stated number of equal parts.

Percentage change is change divided by the original value, multiplied by 100. Profit percentage normally uses cost price; discount percentage uses the marked price. Simple interest is I = Prt/100 when r is an annual percentage and t is in years.

For an examination tax or share question, use the rate and price supplied. Percentage error is absolute error divided by the accepted value, multiplied by 100. Keep extra digits during working and round the final answer to the requested accuracy.

Work through an example

Share ₦18,000 in the ratio 2:3.

Explanation: There are 5 parts. One part is ₦3,600, giving ₦7,200 and ₦10,800.

Watch out: A 20% rise followed by a 20% fall does not restore the starting value.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

Simple interest on ₦8,000 at 5% a year for 2 years is

  1. ₦1,600
  2. ₦800
  3. ₦8,800
  4. ₦400
Show answer and explanation

Answer B: ₦800

I = 8000×5×2/100 = ₦800; ₦8,800 is the total amount.

Question 2

Round 0.004786 to three significant figures.

  1. 0.00479
  2. 0.005
  3. 0.00478
  4. 0.00480
Show answer and explanation

Answer A: 0.00479

The first significant digit is 4. Keep 478 and round up because the next digit is 6.

03 Number and numeration

Indices, logarithms and surds

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What you should be able to do

  • Use index and logarithm laws
  • Simplify surds and standard form

Understand it

For the same positive base, multiply powers by adding indices and divide by subtracting indices. Raising a power to another power multiplies the indices. A negative index indicates a reciprocal; a fractional index indicates a root.

logₐx = y means aʸ = x, where a is positive and not 1 and x is positive. Products become sums of logarithms, quotients become differences, and powers become multipliers. Change base using logₐx = logᵦx/logᵦa.

Simplify a surd by removing square factors. Rationalise a denominator using a suitable surd or conjugate. For a nonzero number, standard form is A×10ⁿ with 1 ≤ |A| < 10 and integer n. For positive numbers this becomes 1 ≤ A < 10; it is useful for very large and very small quantities.

Work through an example

Simplify √72.

Explanation: 72 = 36×2, so √72 = √36×√2 = 6√2.

Watch out: log(a+b) is not log a + log b.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

If 2ˣ = 32, x is

  1. 5
  2. 16
  3. 6
  4. 4
Show answer and explanation

Answer A: 5

32 = 2⁵, so x = 5.

Question 2

What is log₁₀(1000)?

  1. 10
  2. 100
  3. 3
  4. 2
Show answer and explanation

Answer C: 3

10³ = 1000, so the logarithm is 3.

04 Number and numeration

Sets and Venn diagrams

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What you should be able to do

  • Interpret set notation and complements
  • Count members of overlapping sets

Understand it

A set is a collection of distinct objects. A subset contains only members of another set. The universal set fixes the objects under discussion; the complement of A contains its members that are not in A.

A ∪ B includes members of A or B or both. A ∩ B includes members common to both. For two finite sets, n(A ∪ B) = n(A) + n(B) − n(A ∩ B).

In a Venn diagram, fill the most restricted overlaps first. For three sets, begin with the central overlap, then the pair-only regions, then the single-only regions. Count the outside region only when the question includes neither set.

Work through an example

Of 40 students, 22 study French, 18 study Arabic and 7 study both. How many study neither?

Explanation: The union has 22 + 18 − 7 = 33 students. Neither = 40 − 33 = 7.

Watch out: Students in both groups must not be counted twice in the union.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

If A={1,2,3} and B={3,4}, A ∩ B is

  1. {3}
  2. {1,2}
  3. {1,2,3,4}
  4. {4}
Show answer and explanation

Answer A: {3}

Only 3 belongs to both sets.

Question 2

If U={1,2,3,4,5} and A={2,4}, A complement is

  1. {1,3,5}
  2. {1,2,3}
  3. {5}
  4. {2,4}
Show answer and explanation

Answer A: {1,3,5}

Remove members of A from the universal set.

05 Algebra

Polynomials, factors and equations

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What you should be able to do

  • Factorise polynomials and use the remainder theorem
  • Solve linked equations and rearrange formulae

Understand it

A polynomial is built from constant multiples of non-negative whole-number powers of a variable. Collect like terms before multiplying, factorising or evaluating it. To rearrange a formula, perform the same inverse operation on both sides.

The remainder when f(x) is divided by x−a is f(a). Therefore x−a is a factor exactly when f(a)=0. Factor a cubic by finding one root, dividing by its linear factor and then factorising the resulting quadratic.

To solve one linear and one quadratic equation together, express one variable from the linear equation and substitute into the quadratic. A graph crosses or touches the x-axis at real roots; the y-intercept is f(0).

Work through an example

Solve x²−5x+6=0.

Explanation: Factorise as (x−2)(x−3)=0. Hence x=2 or x=3.

Watch out: A factor x+2 corresponds to the root −2, not +2.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The remainder when x³−2x+5 is divided by x−2 is

  1. 11
  2. 5
  3. 7
  4. 9
Show answer and explanation

Answer D: 9

Substitute x=2: 8−4+5=9.

Question 2

Rearrange v=u+at to make t the subject, where a ≠ 0.

  1. (v−u)/a
  2. a(v−u)
  3. (u−v)/a
  4. v−u/a
Show answer and explanation

Answer A: (v−u)/a

Subtract u from both sides, then divide the whole difference by a.

06 Algebra

Variation

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What you should be able to do

  • Build direct, inverse and joint variation equations
  • Determine constants from given data

Understand it

If y varies directly as x, write y=kx. If y varies inversely as x, write y=k/x. The constant k is found from a known pair of values before predicting another pair.

Joint variation combines variables: y varies directly as x and z means y=kxz. If y varies directly as x and inversely as z², write y=kx/z². Read the words before choosing the formula.

Partial variation includes a fixed amount and a varying part, such as a delivery charge y=a+bx. Two data pairs are usually needed to determine both a and b. A proportional relationship passes through the origin; partial variation need not.

Work through an example

If y varies inversely as x and y=6 when x=4, find y when x=8.

Explanation: k=xy=24. Therefore y=24/8=3.

Watch out: Inverse variation uses a constant product, not a constant ratio.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

If y∝x² and y=12 when x=2, find y at x=3.

  1. 24
  2. 36
  3. 27
  4. 18
Show answer and explanation

Answer C: 27

k=12/4=3, so y=3×9=27.

Question 2

Which equation describes partial variation?

  1. y=4x²
  2. y=4/x
  3. y=4+x
  4. y=4x
Show answer and explanation

Answer C: y=4+x

y=4+x includes a fixed part 4 and a part varying directly as x.

07 Algebra

Linear and quadratic inequalities

Read this lesson

What you should be able to do

  • Solve inequalities and show solution intervals
  • Interpret inequalities on number lines and graphs

Understand it

Solve a linear inequality much like an equation, but reverse its sign when multiplying or dividing by a negative number. Strict signs < and > exclude an endpoint; ≤ and ≥ include it.

For a quadratic inequality, factorise and mark the roots on a number line. Test the sign in each interval. A positive-leading quadratic is positive outside two distinct real roots and negative between them.

A two-variable linear inequality describes a half-plane. Draw the boundary line, choose a test point such as (0,0) when it is not on the line, and shade the side that satisfies the inequality.

Work through an example

Solve −2x<6.

Explanation: Divide by −2 and reverse the sign: x>−3.

Watch out: Do not reverse an inequality merely because a term is moved across the sign.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

Solve x²−5x+6<0.

  1. x<2 or x>3
  2. 2<x<3
  3. x<2
  4. x>3
Show answer and explanation

Answer B: 2<x<3

(x−2)(x−3) is negative between the roots.

Question 2

Solve 3x+1≤10.

  1. x<3
  2. x≥3
  3. x≤9
  4. x≤3
Show answer and explanation

Answer D: x≤3

Subtract 1, then divide by positive 3 without reversing the sign.

08 Algebra

Arithmetic and geometric progressions

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What you should be able to do

  • Find terms and sums of APs and GPs
  • Recognise constant differences and ratios

Understand it

An arithmetic progression has a constant difference d. Its nth term is a+(n−1)d and the sum of n terms is n[2a+(n−1)d]/2. Check that the number of terms is a whole number.

A geometric progression has a constant ratio r. Its nth term is arⁿ⁻¹. For r≠1, its finite sum is a(1−rⁿ)/(1−r); when r=1 the sum is na.

An infinite GP has a finite sum a/(1−r) only when |r|<1. A negative ratio produces alternating signs. Do not assume every sequence is an AP or GP: test consecutive differences or ratios first.

Work through an example

Find the tenth term of 3, 7, 11, ...

Explanation: a=3 and d=4, so T₁₀=3+9×4=39.

Watch out: The nth term contains n−1 steps after the first term.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The sum of the first five terms of 2,4,6,... is

  1. 20
  2. 25
  3. 30
  4. 35
Show answer and explanation

Answer C: 30

2+4+6+8+10=30.

Question 2

The fourth term of 3,6,12,... is

  1. 24
  2. 48
  3. 21
  4. 18
Show answer and explanation

Answer A: 24

a=3, r=2, so T₄=3×2³=24.

09 Algebra

Binary operations

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What you should be able to do

  • Evaluate an operation defined by a rule
  • Check identity, inverse and algebraic properties

Understand it

A binary operation combines two members of a set using a stated rule. For a*b=a+b+ab, the symbol * does not mean ordinary multiplication. Substitute both values into the whole rule.

Closure means the result remains in the set. Commutativity means a*b=b*a, while associativity means (a*b)*c=a*(b*c). Test the actual rule; an operation can have one property without the other.

An identity e satisfies a*e=e*a=a for every member. An inverse of a combines with a to give that identity. Whether an inverse exists depends on the operation and the set.

Work through an example

For a*b=a+b+ab, calculate 2*3.

Explanation: 2*3=2+3+(2×3)=11.

Watch out: The identity is not always 1; it depends on the rule.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

For a*b=a+b−2, the identity is

  1. 1
  2. 2
  3. −2
  4. 0
Show answer and explanation

Answer B: 2

a*2=a+2−2=a and 2*a=a.

Question 2

For a*b=a−b on integers, which is true?

  1. Always associative
  2. Always commutative
  3. Has a two-sided identity 0
  4. Closed on integers
Show answer and explanation

Answer D: Closed on integers

Subtracting two integers gives an integer; subtraction is not commutative or associative and 0−a differs from a.

10 Algebra

Matrices and determinants

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What you should be able to do

  • Perform matrix operations and evaluate determinants
  • Find a 2 by 2 inverse when it exists

Understand it

A matrix arranges numbers in rows and columns. Addition and subtraction require equal dimensions. To multiply A by B, the number of columns of A must equal the number of rows of B; each entry is a row-by-column sum.

For a 2 by 2 matrix [[a,b],[c,d]], the determinant is ad−bc. Its inverse is (1/(ad−bc))[[d,−b],[−c,a]], provided the determinant is not zero. A zero determinant means the inverse does not exist.

For a 3 by 3 determinant, expand along a convenient row or column using alternating signs. Matrix multiplication is generally not commutative. A square identity matrix has 1s on the main diagonal and 0s elsewhere.

Work through an example

Find the determinant of [[2,1],[3,4]].

Explanation: det = (2×4)−(1×3)=5.

Watch out: Subtract bc from ad; do not add the two diagonal products.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The determinant of [[1,2],[2,4]] is

  1. 4
  2. 0
  3. 2
  4. 8
Show answer and explanation

Answer B: 0

1×4−2×2=0, so the matrix is singular.

Question 2

A 2×3 matrix multiplied by a 3×4 matrix gives a

  1. 4×2 matrix
  2. Product that is undefined
  3. 3×3 matrix
  4. 2×4 matrix
Show answer and explanation

Answer D: 2×4 matrix

The inner dimensions match; the result uses the outer dimensions.

11 Geometry and trigonometry

Angles, polygons and circle geometry

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What you should be able to do

  • Use angle facts in lines, polygons and circles
  • Link constructions to geometric properties

Understand it

Angles on a straight line total 180° and angles around a point total 360°. Parallel lines produce equal corresponding and alternate angles; co-interior angles total 180°. A triangle has angle sum 180°.

The interior-angle sum of an n-sided polygon is (n−2)180°. A regular polygon has equal sides and angles, and each exterior angle is 360°/n. Construction methods use equal radii, angle bisectors and perpendicular bisectors.

In a circle, the angle at the centre is twice the angle at the circumference standing on the same arc. Opposite angles in a cyclic quadrilateral total 180°. A tangent is perpendicular to the radius at contact; intersecting chords satisfy the product-of-segments rule.

Work through an example

One angle of a cyclic quadrilateral is 112°. Find the opposite angle.

Explanation: Opposite angles sum to 180°, so the required angle is 68°.

Watch out: Equal angles in the same segment must stand on the same chord.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

Each exterior angle of a regular hexagon is

  1. 60°
  2. 45°
  3. 90°
  4. 120°
Show answer and explanation

Answer A: 60°

360°/6=60°.

Question 2

An angle subtended by a diameter at the circumference is

  1. 180°
  2. 90°
  3. 60°
  4. 45°
Show answer and explanation

Answer B: 90°

It stands on a semicircle and is a right angle.

12 Geometry and trigonometry

Mensuration, solids and the Earth

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What you should be able to do

  • Calculate areas, volumes and surface areas
  • Use circle angles and spherical distances

Understand it

Keep length, area and volume units separate. A circle has area πr² and circumference 2πr. A sector of angle θ degrees has area θπr²/360 and arc length θ2πr/360. For a minor segment, subtract the triangle formed by the two radii and chord from the minor sector. The corresponding major segment is the whole circle minus that minor segment.

A prism has volume equal to cross-sectional area times length. A cylinder has volume πr²h; a cone has πr²h/3; a sphere has 4πr³/3. For a composite solid, add or subtract the volumes and count only exposed surfaces.

On a spherical Earth of radius R, a central angle θ radians subtends distance Rθ along a great circle. A parallel at latitude φ has radius R cosφ. Longitude distances along that parallel therefore use R cosφ rather than R.

Work through an example

Find the volume of a cylinder of radius 3 cm and height 5 cm.

Explanation: V=π×3²×5=45π cm³.

Watch out: A diameter must be halved before it is used as a radius.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The area of a 90° sector of radius 4 cm is

  1. 16π cm²
  2. 8π cm²
  3. 2π cm²
  4. 4π cm²
Show answer and explanation

Answer D: 4π cm²

It is one quarter of π×16, giving 4π cm².

Question 2

Doubling every length of a cube multiplies its volume by

  1. 8
  2. 6
  3. 2
  4. 4
Show answer and explanation

Answer A: 8

Volume scales with the cube of the length factor: 2³=8.

13 Geometry and trigonometry

Loci and constructions

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What you should be able to do

  • Identify common two-dimensional loci
  • Combine geometric conditions

Understand it

A locus is the set of points satisfying a condition. Points a fixed distance from a fixed point form a circle. Points equally distant from two fixed points lie on the perpendicular bisector of the segment joining them.

Points a fixed distance from a straight line form two parallel lines, one on either side. Points equally distant from two intersecting lines lie on their angle bisectors. A locus may contain more than one branch.

When two conditions apply together, construct both loci and identify their intersections. Compass arcs preserve equal distances, while a straightedge joins known points. Keep construction arcs visible when a practical construction is requested.

Work through an example

Where can a point be equally distant from towns A and B and 5 km from A?

Explanation: It must lie at an intersection of the perpendicular bisector of AB and the circle centred at A with radius 5 km.

Watch out: A locus is the entire set of allowed positions, not one example point.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The locus of points 3 cm from O is a

  1. Straight line
  2. Perpendicular bisector
  3. Circle centred at O
  4. Single point
Show answer and explanation

Answer C: Circle centred at O

Every point on that circle has distance 3 cm from O.

Question 2

Points equally distant from two intersecting lines lie on their

  1. Circumference
  2. Angle bisectors
  3. Parallel lines
  4. Common midpoint
Show answer and explanation

Answer B: Angle bisectors

Perpendicular distance to each line is equal on either angle bisector.

14 Geometry and trigonometry

Coordinate geometry

Read this lesson

What you should be able to do

  • Find distances, midpoints and gradients
  • Write equations of straight lines

Understand it

For points (x₁,y₁) and (x₂,y₂), the midpoint is ((x₁+x₂)/2,(y₁+y₂)/2). Their distance is √[(x₂−x₁)²+(y₂−y₁)²], obtained from Pythagoras.

The gradient is (y₂−y₁)/(x₂−x₁) for a non-vertical line. Parallel non-vertical lines have equal gradients. Perpendicular lines with defined nonzero gradients have product −1.

A line of gradient m through (x₁,y₁) has equation y−y₁=m(x−x₁). In y=mx+c, c is the y-intercept. A vertical line instead has equation x=k and an undefined gradient.

Work through an example

Find the equation through (2,3) with gradient 4.

Explanation: y−3=4(x−2), so y=4x−5.

Watch out: A horizontal line has gradient 0; a vertical line has undefined gradient.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The midpoint of (−2,4) and (6,2) is

  1. (2,2)
  2. (−4,1)
  3. (4,6)
  4. (2,3)
Show answer and explanation

Answer D: (2,3)

Average the x-coordinates and the y-coordinates separately.

Question 2

A line perpendicular to y=2x+1 has gradient

  1. 2
  2. −1/2
  3. 1/2
  4. −2
Show answer and explanation

Answer B: −1/2

The negative reciprocal of 2 is −1/2.

15 Geometry and trigonometry

Trigonometric ratios, bearings and triangles

Read this lesson

What you should be able to do

  • Choose trigonometric rules for triangles
  • Interpret bearings and elevation angles

Understand it

In a right triangle, sinθ=opposite/hypotenuse, cosθ=adjacent/hypotenuse and tanθ=opposite/adjacent. The side names depend on the angle chosen. Pythagoras applies only to right triangles.

For any triangle, a/sinA=b/sinB=c/sinC. The cosine rule is a²=b²+c²−2bc cosA, and area=½bc sinA. Use a sketch to match a side with its opposite angle; sine-rule problems may have two possible triangles.

Bearings are measured clockwise from north and normally written with three digits. Elevation and depression angles are measured from a horizontal line. Sine and cosine graphs repeat every 360° or 2π radians; convert units before calculating.

Work through an example

A right triangle has opposite side 3 and hypotenuse 5 for angle θ. Find sinθ.

Explanation: sinθ=3/5.

Watch out: A bearing of 060° is measured from north, not from east.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The area of a triangle with sides 6 cm and 8 cm enclosing 30° is

  1. 24 cm²
  2. 48 cm²
  3. 36 cm²
  4. 12 cm²
Show answer and explanation

Answer D: 12 cm²

½×6×8×sin30° = 12 cm².

Question 2

If a location is due west, its bearing is

  1. 270°
  2. 180°
  3. 000°
  4. 090°
Show answer and explanation

Answer A: 270°

Clockwise from north, west is 270°.

16 Calculus

Limits and differentiation

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What you should be able to do

  • Interpret a derivative as a limiting rate
  • Differentiate powers and basic trigonometric functions

Understand it

A limit describes the value a function approaches as its input approaches a point. A removable factor may allow a limit to exist even when the original expression is undefined at that point.

The derivative gives instantaneous rate of change and the gradient of a tangent. For y=xⁿ, dy/dx=nxⁿ⁻¹. A constant differentiates to zero; differentiate a sum term by term.

With angles in radians, d(sinx)/dx=cosx, d(cosx)/dx=−sinx and d(tanx)/dx=sec²x. For a composite expression, the chain rule also multiplies by the derivative of its inner expression.

Work through an example

Differentiate y=3x²−4x+7.

Explanation: dy/dx=6x−4. The derivative of the constant 7 is zero.

Watch out: Differentiating xⁿ decreases the power by one; integrating increases it.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The derivative of 5x³ is

  1. 15x²
  2. 5x²
  3. 10x²
  4. 15x³
Show answer and explanation

Answer A: 15x²

Multiply by the old power 3, then reduce the power to 2.

Question 2

Find lim as x→2 of (x²−4)/(x−2).

  1. Undefined limit
  2. 2
  3. 4
  4. 0
Show answer and explanation

Answer C: 4

For x≠2, factor and cancel to obtain x+2; its limit is 4.

17 Calculus

Rates of change and turning points

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What you should be able to do

  • Apply derivatives to motion and optimisation
  • Classify stationary points

Understand it

If displacement is s(t), velocity is ds/dt and acceleration is d²s/dt². The variables and units matter: a derivative with respect to time is a rate per unit time.

A stationary point has first derivative zero. A positive second derivative indicates a local minimum and a negative second derivative indicates a local maximum. If the second derivative is zero, another test is needed.

For an optimisation question, write the quantity to maximise or minimise in one variable, state the allowed domain and test stationary points and relevant endpoints. An algebraic stationary point outside the physical domain is not a valid answer.

Work through an example

Find the minimum of y=x²−6x+11.

Explanation: dy/dx=2x−6=0 gives x=3. The second derivative is 2>0. At x=3, y=2.

Watch out: Zero first derivative alone does not prove that a point is a maximum.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

If s=2t²+3t, velocity at t=2 is

  1. 14
  2. 7
  3. 8
  4. 11
Show answer and explanation

Answer D: 11

v=4t+3; substituting t=2 gives 11 units per unit time.

Question 2

A stationary point with second derivative −4 is a local

  1. Maximum
  2. Vertical asymptote
  3. Minimum
  4. Point with no classification
Show answer and explanation

Answer A: Maximum

A negative second derivative means the curve bends downwards there.

18 Calculus

Integration and area

Read this lesson

What you should be able to do

  • Find antiderivatives
  • Use definite integrals to calculate signed area

Understand it

Integration reverses differentiation. For n≠−1, ∫xⁿdx=xⁿ⁺¹/(n+1)+C. An indefinite integral needs the constant C because many functions have the same derivative.

For angles in radians, ∫cosx dx=sinx+C and ∫sinx dx=−cosx+C. Check an antiderivative by differentiating it. Keep coefficients outside the integral when convenient.

A definite integral from a to b equals F(b)−F(a). It gives signed area: regions below the x-axis contribute negatively. For total geometric area, split at x-axis crossings and add positive area magnitudes.

Work through an example

Evaluate ∫ from 0 to 2 of 3x² dx.

Explanation: An antiderivative is x³. The integral is 2³−0³=8.

Watch out: The power rule above does not apply to x⁻¹.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

An antiderivative of 4x is

  1. 4x²+C
  2. 2x²+C
  3. 4+C
  4. x⁴+C
Show answer and explanation

Answer B: 2x²+C

Differentiate 2x² to recover 4x.

Question 2

The area under y=2 between x=1 and x=4 is

  1. 4
  2. 3
  3. 6
  4. 8
Show answer and explanation

Answer C: 6

The region is a rectangle of height 2 and width 3, so its area is 6.

19 Statistics

Representing data

Read this lesson

What you should be able to do

  • Construct and interpret frequency tables and charts
  • Distinguish categorical and continuous displays

Understand it

A frequency table counts how often values or classes occur. Categories are separate labels, while continuous data can take values across an interval. Choose a display that fits the type of data.

A bar chart has separate bars for categories. A histogram uses touching intervals; when class widths differ, bar height must be frequency density, equal to frequency divided by class width. Histogram area then represents frequency.

In a pie chart, sector angle is category frequency divided by total frequency, multiplied by 360°. Read scales carefully and check whether a graph begins at zero before comparing visual differences.

Work through an example

In a survey of 60 students, 15 chose football. Find its pie-chart angle.

Explanation: 15/60×360°=90°.

Watch out: With unequal histogram widths, height alone does not show frequency.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

A histogram class has frequency 20 and width 5. Its frequency density is

  1. 5
  2. 100
  3. 4
  4. 15
Show answer and explanation

Answer C: 4

Density=20/5=4.

Question 2

Which display is most directly suited to comparing named transport types?

  1. Cumulative curve only
  2. Bar chart
  3. Continuous histogram only
  4. Scatter graph only
Show answer and explanation

Answer B: Bar chart

Separate categories are represented naturally by separate bars.

20 Statistics

Mean, median, mode and cumulative frequency

Read this lesson

What you should be able to do

  • Calculate location measures
  • Estimate medians from grouped data

Understand it

The arithmetic mean is the total of all values divided by their number. For a frequency table it is Σfx/Σf. For grouped data, using class midpoints gives an estimate rather than the exact mean.

The median is the middle value after sorting. For an even number of observations, average the two middle values. The mode is the most frequent value or category; a dataset can have more than one mode.

Cumulative frequency adds frequencies successively and helps locate medians and quartiles. On a grouped cumulative-frequency curve, use the appropriate fraction of the total on the frequency axis and read the estimated data value.

Work through an example

Find the mean, median and mode of 2,3,3,8.

Explanation: Mean=16/4=4. Median=(3+3)/2=3. Mode=3.

Watch out: Sort observations before locating the median.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The median of 7,1,5 is

  1. 1
  2. 5
  3. 7
  4. 4
Show answer and explanation

Answer B: 5

Sorted values are 1,5,7; the middle value is 5.

Question 2

For values 2 and 5 with frequencies 3 and 1, the mean is

  1. 5.5
  2. 7
  3. 3.5
  4. 2.75
Show answer and explanation

Answer D: 2.75

Σfx=2×3+5×1=11 and total frequency is 4; mean=2.75.

21 Statistics

Range, variance and standard deviation

Read this lesson

What you should be able to do

  • Measure the spread of data
  • Interpret changes in location and scale

Understand it

The range is largest minus smallest value. It is easy to calculate but uses only two observations. Mean absolute deviation averages the absolute distances of observations from their mean.

Population variance is Σ(x−mean)²/n, or Σf(x−mean)²/Σf for a frequency table. Standard deviation is its non-negative square root and has the same units as the data. Use a sample formula only when the question specifies that convention.

Adding the same constant to every value shifts the mean but leaves variance unchanged. Multiplying every value by k multiplies standard deviation by |k| and variance by k². Spread compares consistency, not which dataset has a higher average.

If every observation is the same, all deviations from the mean are zero. Both variance and standard deviation are then zero.

Work through an example

Find the population variance of 2,4,6.

Explanation: The mean is 4. Squared deviations are 4,0,4. Variance=8/3; standard deviation=√(8/3).

Watch out: Variance has squared units; standard deviation returns to the original units.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

The range of 3,9,4,6 is

  1. 5
  2. 9
  3. 3
  4. 6
Show answer and explanation

Answer D: 6

Largest 9 minus smallest 3 equals 6.

Question 2

Every observation is multiplied by 3. The variance becomes

  1. 9 times as large
  2. 6 times as large
  3. Unchanged
  4. 3 times as large
Show answer and explanation

Answer A: 9 times as large

Variance scales as the square of the multiplier: 3²=9.

22 Statistics

Permutations and combinations

Read this lesson

What you should be able to do

  • Count selections and arrangements
  • Handle repeated objects and circular arrangements

Understand it

Use multiplication when a task has successive independent choices. Factorial n! counts arrangements of n distinct objects. A permutation selects and orders r objects: nPr=n!/(n−r)!.

A combination selects without order: nCr=n!/[r!(n−r)!]. Choose the method by asking whether swapping selected objects creates a new outcome. A committee is normally a combination; assigning different offices is a permutation.

For arrangements with repeated indistinguishable objects, divide by the factorials of the repeated counts. Distinct people around an unmarked circular table have (n−1)! arrangements when rotations count as the same; extra symmetry rules must be stated.

Work through an example

How many pairs can be chosen from five students?

Explanation: 5C2=5!/(2!3!)=10 pairs.

Watch out: Do not count AB and BA twice when only selecting a pair.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

How many ways can three distinct books be arranged in a row?

  1. 3
  2. 27
  3. 6
  4. 9
Show answer and explanation

Answer C: 6

3!=3×2×1=6.

Question 2

How many distinct arrangements does the word MAMA have?

  1. 4
  2. 6
  3. 12
  4. 24
Show answer and explanation

Answer B: 6

There are 4!/(2!2!)=6 arrangements because M and A each repeat twice.

23 Statistics

Probability

Read this lesson

What you should be able to do

  • Calculate probabilities from equally likely outcomes
  • Distinguish independent and mutually exclusive events

Understand it

For equally likely outcomes, probability equals favourable outcomes divided by total outcomes. Probabilities lie between 0 and 1, and the complement rule is P(not A)=1−P(A). Experimental probability uses observed relative frequency.

For any two events, P(A or B)=P(A)+P(B)−P(A and B). Mutually exclusive events cannot happen together, so their overlap is zero. Independence instead means that knowing one occurred does not change the probability of the other.

For independent events, multiply probabilities to find the probability of both. Without replacement, probabilities often change after the first selection; update both the number of favourable objects and the total.

Work through an example

A bag has 3 red and 2 blue balls. Two are drawn without replacement. Find the probability both are red.

Explanation: (3/5)×(2/4)=3/10.

Watch out: Independent and mutually exclusive do not mean the same thing.

2 practice questions with answers

Try each question before opening its answer. These are original CampusNinja practice questions.

Question 1

A fair die is rolled. Probability of a number greater than 4 is

  1. 2/3
  2. 1/6
  3. 1/3
  4. 1/2
Show answer and explanation

Answer C: 1/3

Favourable numbers are 5 and 6: 2/6=1/3.

Question 2

Two fair coins are tossed. Probability of exactly one head is

  1. 3/4
  2. 1/2
  3. 1/4
  4. 1
Show answer and explanation

Answer B: 1/2

HT and TH are two of four equally likely outcomes.

Syllabus source and learning material

Scope checked against JAMB’s IBASS source on 2026-10-16. Current IBASS file; not independently labelled 2027. Notes, examples and practice questions are original CampusNinja learning material, not authenticated JAMB past questions.

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